4=2x^2/(1-x)

Solution for 4=2x^2/(1-x) equation:

4=2x^2/(1-x)

We move all terms to the left:

4-(2x^2/(1-x))=0


Domain of the equation: (1-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-1

x!=-1/1

x!=-1

x∈R


We add all the numbers together, and all the variables

-(2x^2/(-1x+1))+4=0

We multiply all the terms by the denominator


-(2x^2+4*(-1x+1))=0


We calculate terms in parentheses: -(2x^2+4*(-1x+1)), so:

2x^2+4*(-1x+1)

We multiply parentheses

2x^2-4x+4

Back to the equation:

-(2x^2-4x+4)


We get rid of parentheses

-2x^2+4x-4=0

a = -2; b = 4; c = -4;
Δ = b2-4ac
Δ = 42-4·(-2)·(-4)
Δ = -16
Delta is less than zero, so there is no solution for the equation